When `Cl_2` gas is passed through hot and conc. solution of KOH, following compound is formed

Options

A. KCI
B. `KClO_3`
C. `KClO_2`
D. `KClO_4`

Explanation

To determine the compound formed when chlorine gas (Cl₂) is passed through a hot and concentrated solution of potassium hydroxide (KOH), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: We have chlorine gas (Cl₂) and a concentrated solution of potassium hydroxide (KOH).

2. **Understand the Reaction Conditions**: The reaction occurs under hot and concentrated conditions, which can influence the products formed.

3. **Write the Reaction**: When Cl₂ reacts with KOH, it can lead to the formation of potassium chlorate (KClO₃) along with water (H₂O). The balanced chemical equation for this reaction is:
\[ 3 \text{Cl}_2 + 6 \text{KOH} \rightarrow 5 \text{KCl} + \text{KClO}_3 + 3 \text{H}_2\text{O} \]

4. **Identify the Product**: From the balanced equation, we can see that potassium chlorate (KClO₃) is one of the products formed in the reaction.

5. **Conclusion**: Therefore, when chlorine gas is passed through a hot and concentrated solution of KOH, the compound formed is potassium chlorate (KClO₃).

### Final Answer:
The compound formed is **KClO₃** (Potassium Chlorate).

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