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The value of sqrt18 + sqrt50 - sqrt32 is...

The value of `sqrt18 + sqrt50 - sqrt32` is

A

`4 sqrt2`

B

`3 sqrt2`

C

`2sqrt2`

D

`sqrt2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \sqrt{18} + \sqrt{50} - \sqrt{32} \), we will simplify each square root term step by step. ### Step 1: Simplify \( \sqrt{18} \) - The prime factorization of \( 18 \) is \( 2 \times 3^2 \). - Therefore, we can write: \[ \sqrt{18} = \sqrt{2 \times 3^2} = \sqrt{2} \times \sqrt{3^2} = \sqrt{2} \times 3 = 3\sqrt{2} \] ### Step 2: Simplify \( \sqrt{50} \) - The prime factorization of \( 50 \) is \( 2 \times 5^2 \). - Thus, we have: \[ \sqrt{50} = \sqrt{2 \times 5^2} = \sqrt{2} \times \sqrt{5^2} = \sqrt{2} \times 5 = 5\sqrt{2} \] ### Step 3: Simplify \( \sqrt{32} \) - The prime factorization of \( 32 \) is \( 2^5 \). - We can express this as: \[ \sqrt{32} = \sqrt{2^5} = \sqrt{(2^4) \times 2} = \sqrt{2^4} \times \sqrt{2} = 4\sqrt{2} \] ### Step 4: Substitute back into the expression Now, we substitute the simplified square roots back into the original expression: \[ \sqrt{18} + \sqrt{50} - \sqrt{32} = 3\sqrt{2} + 5\sqrt{2} - 4\sqrt{2} \] ### Step 5: Combine like terms Combine the terms: \[ (3 + 5 - 4)\sqrt{2} = 4\sqrt{2} \] ### Final Answer The value of \( \sqrt{18} + \sqrt{50} - \sqrt{32} \) is: \[ \boxed{4\sqrt{2}} \]
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