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If log(a)m = x, then log(1//a) ""(1)/(m)...

If `log_(a)m = x,` then `log_(1//a) ""(1)/(m)` is equal to

A

x

B

`-x`

C

`(1)/(x)`

D

`(-1)/(x)`

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AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given information and apply logarithmic properties step by step. ### Step-by-Step Solution: 1. **Given Information**: We know that \( \log_a m = x \). This means that \( a^x = m \). 2. **Express the Required Logarithm**: We need to find \( \log_{(1/a)} \left( \frac{1}{m} \right) \). 3. **Using the Change of Base Formula**: We can rewrite the logarithm using the change of base formula: \[ \log_{(1/a)} \left( \frac{1}{m} \right) = \frac{\log \left( \frac{1}{m} \right)}{\log \left( \frac{1}{a} \right)} \] 4. **Simplifying the Logarithms**: - The logarithm of a reciprocal can be expressed as: \[ \log \left( \frac{1}{m} \right) = \log 1 - \log m = 0 - \log m = -\log m \] - Similarly, for \( \log \left( \frac{1}{a} \right) \): \[ \log \left( \frac{1}{a} \right) = \log 1 - \log a = 0 - \log a = -\log a \] 5. **Substituting Back**: Now substituting these results back into our expression: \[ \log_{(1/a)} \left( \frac{1}{m} \right) = \frac{-\log m}{-\log a} = \frac{\log m}{\log a} \] 6. **Using the Given Information**: We know from the problem statement that \( \log_a m = x \), which can be expressed as: \[ \frac{\log m}{\log a} = x \] 7. **Final Result**: Therefore, we conclude that: \[ \log_{(1/a)} \left( \frac{1}{m} \right) = x \] ### Final Answer: \[ \log_{(1/a)} \left( \frac{1}{m} \right) = x \]
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