A 200g block while sinking in water, displaces 25g of water. If we leave the block in water independently then, then block will

Options

A. sink
B. float with whole volume
C. partially float
D. None of the above

Answer

To solve the problem, we need to analyze the situation of the 200g block displacing 25g of water. We will use Archimedes' principle to determine whether the block sinks, floats, or partially floats when placed in water.

### Step-by-Step Solution:

1. **Understanding the Given Data:**
- Mass of the block (m_block) = 200g
- Mass of the water displaced (m_water_displaced) = 25g

2. **Applying Archimedes' Principle:**
- According to Archimedes' principle, the buoyant force (B) acting on the block is equal to the weight of the water displaced.
- The weight of the displaced water can be calculated as:
\[ B = m_{water\_displaced} \cdot g \]
where \( g \) is the acceleration due to gravity. However, since we are comparing masses, we can ignore \( g \) for this analysis.

3. **Calculating the Buoyant Force:**
- The buoyant force is equal to the mass of the water displaced:
\[ B = 25g \]

4. **Comparing the Weight of the Block and the Buoyant Force:**
- The weight of the block is:
\[ W_{block} = m_{block} = 200g \]
- Now we compare the weight of the block with the buoyant force:
\[ W_{block} (200g) > B (25g) \]
- Since the weight of the block is greater than the buoyant force, the block will not float.

5. **Conclusion:**
- Since the block is heavier than the buoyant force acting on it, it will sink. However, since it displaces some water, it will not sink completely without any resistance. Therefore, the block will partially float.

### Final Answer:
The block will partially float.