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The equilibrium constant for the followi...

The equilibrium constant for the following reaction at 298K is expressed as `x xx 10^(y)`.
`2Fe^(3+) + 2I^(-) rarr 2Fe^(2+) + I_(2), E_("cell")^(@) = 0.236V`. The value of y is …..

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The correct Answer is:
B

`E_("cell")^(@) = (0.059)/(2) log K_(c ) rArr log K_(c )= ((2 xx 0.236)/(0.059))= 8 rArr K = x xx10^(8)`
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