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One gram of metal M^(3+) was discharged ...

One gram of metal `M^(3+)` was discharged by the passage of `1.81 xx 10^(23)` electrons. What is the atomic weight of the metal?

A

`33.35`

B

`133.4`

C

`66.7`

D

`9.98`

Text Solution

Verified by Experts

The correct Answer is:
D
When 1 mole of `e^(-)` passed, wt of substance deposited `=(1 xx 6.023 xx 10^(23))/(1.81 xx 10^(23)) rArr 3.33g` = eq wt `therefore` Atomic wt of metal `=3.33 xx 3= 9.98g`
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