The equilibrium constant of acetic acid in an aqueous solution of concentration c is given by

Options

A. `K= (c Lamda_(e)^(2))/(Lamda^(prop)-Lamda_(c ))`
B. `K = (c Lamda_(c)^(2))/(Lamda^(prop) (Lamda^(prop)-Lamda_(c )))`
C. `K= (c Lamda_(c )^(2))/(Lamda^(prop) + Lamda_(c ))`
D. `K= (c Lamda_(c )^(2))/(Lamda^(prop) (Lamda- Lamda_(c )))`

Answer

B

Explanation

`underset(c (t-alpha))(CH_(3)COOH) hArr underset(c alpha)(CH_(3)COO^(-)) + underset(c alpha)(H^(+)), K = ([CH_(3)COO^(-)][H^(+)])/([CH_(3)COOH])= (c alpha^(2))/((1-alpha))`
Since `alpha= Lamda_(c)//Lamda^(oo)`, we get `K= (c(Lamda_(c)//Lamda^(oo))^(2))/(1-(Lamda_(c)//Lamda_(e)))= (c Lamda_(c)^(2))/(Lamda^(oo)(Lamda^(oo)//Lamda_(c )))`