Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mole of `H_(2)` gas at the cathode is:

Options

A. `9.65 xx 10^(4) sec`
B. `19.3 xx 10^(4) sec`
C. `28.95 xx 10^(4) sec`
D. `38.6 xx 10^(4) sec`

Answer

B

Explanation

Mass of 0.01mol `H_(2)= 0.02g, W= (I t E)/(96500), 0.02 (10 xx 10^(-3) xx t xx 1)/(96500), t= 19.3 xx 10 sec`