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A 0.05N solution of a salt occupying a v...

A 0.05N solution of a salt occupying a volume between two platinum electrodes separated by a distance of 1.72cm and having an area of `4.5cm^(2)` has a resistance of 250 ohm. Calculate the equivalent conductance of the solution

A

`48.23 ohm^(-1) cm^(2) eq^(-1)`

B

`62.83 ohm^(-1) cm^(2) eq^(-1)`

C

`22.36 ohm^(-1) cm^(2) eq^(-1)`

D

`30.576 ohm^(-1) cm^(2) eq^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`k= C xx (l)/(A) = (1)/(R ) xx (l)/(A) = (1)/(250) xx (1.72)/(4.5)= 1.5288 xx 10^(-3) ohm^(-1) cm^(-1)`
`Lamda_(c )= k xx (1000)/(N) = 1.5288 xx 10^(-3) xx (1000)/(0.05)= 30.576 ohm^(-1) eq^(-1)`
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