In Fig ., PQRS and ABRS are parallelograms and X is any point on side BR .Show that `ar(PQES)=ar(ABRS)`

In the figure. ABCD is a parallelogram and O is any point on BC . Prove that ar (triangleABO) + ar (triangleDOC) = ar(triangleODA)

ABCD is a parallelogram and X is the mid-point of AB. If ar (AXCD) = 24 cm^2 , then ar (ABC) = 24 cm^2 .

In the figure ABCD and EFGD are two parallelograms and G is the mid-point of CD. Then ar(DPC) = 1/2 ar(EFGD)

E is any point on median AD of a triangle ABC . Show that ar (ABE) = ar (ACE).

In Fig. 9.13, ABCD is a parallelogram and EFCD is a rectangle. Also, AL bot DC . Prove that (i) ar (ABCD) = ar (EFCD) (ii) ar (ABCD) = DC × AL

In Fig. . ABCD is a parallelogram and E is the mid-point of side BC. If DE and AB, when produced meet at F, prove that AF = 2AB.

In Fig. . ABCD is a parallelogram and E is the mid-point of side BC. If DE and AB, when produced meet at F, prove that AF = 2AB.

In Fig. , PQR is a triangle, S is any point in its interior, show that . SQ + SR < PQ + PR .

In Fig. , PQR is a triangle, S is any point in its interior, show that . SQ + SR < PQ + PR .

In the fig. ABCD is a parallelogram and X,Y and Z the points on diagonal BD such that DX=BD prove that CXAY is a parallelogram.