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In Fig ., D and E are two points on BC...

In Fig ., D and E are two points on BC such that BD = DE = EC . Show that ar (ABD) = ar (ADE) = ar (AEC).

Can you now answer the question that you have left in the introduction of this chapter , whether the field of Budhia has been actually divided into three parts of equal area ?

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SWAN PUBLICATION-AREAS OF PARALLELOGRAMS AND TRIANGLES -EXERCISE 9.4
  1. Parallelogram ABCD and rectangle ABEF are on the same base AB and have...

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  2. In Fig ., D and E are two points on BC such that BD = DE = EC . Sh...

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  3. ABCD, DCFE and ABFE are parallelograms. Show that ar(ADE) = ar(BCF)

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  4. ABCD is a parallelogram and BC is produced to a point Q such that AD =...

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  5. ABC and BDE are two equilateral triangles such that D is the mid-point...

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  6. ABC and BDE are two equilateral triangles such that D is the mid-point...

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  7. In Fig ., ABC and BDE are two equilateral triangles such that ...

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  8. ABC and BDE are two equilateral triangles such that D is the mid-point...

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  9. ABC and BDE are two equilateral triangles such that D is the mid-point...

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  10. ABC and BDE are two equilateral triangles such that D is the mid-point...

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  11. Diagonals AC and BD of quadrilateral ABCD intersect each other at P. S...

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  12. P and Q are respectively the midpoints of sides AB and BC or a triangl...

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  13. P and Q are respectively the midpoints of sides AB and BC or a triangl...

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  14. P and Q are respectively the midpoints of sides AB and BC or a triangl...

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  15. In Fig ., ABC is a right triangle right angled at A. BCED , A...

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  16. In Fig ., ABC is a right triangle right angled at A. BCED , A...

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  17. In Fig ., ABC is a right triangle right angled at A. BCED , A...

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  18. In Fig ., ABC is a right triangle right angled at A. BCED , A...

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  19. ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squ...

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  20. ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squ...

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