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A sum amounts to Rs 6,050 in 2 years and...

A sum amounts to Rs 6,050 in 2 years and to Rs 6, 655 in 3 years at a certain rate percentage p.a. when the interest is compounded yearly. What is the simple interest on a sum of Rs 6,000 at the same rate for `5(3)/(4)` years ?

A

Rs 3,450

B

Rs 3,150

C

Rs 3,300

D

Rs 3,200

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The correct Answer is:
To solve the problem step by step, we will first determine the rate of interest using the compound interest information provided and then calculate the simple interest on a sum of Rs 6,000 for the specified time period. ### Step 1: Determine the Rate of Interest We know: - Amount after 2 years (A1) = Rs 6,050 - Amount after 3 years (A2) = Rs 6,655 Using the compound interest formula: \[ A = P \left(1 + \frac{r}{100}\right)^t \] For the first amount: \[ 6050 = P \left(1 + \frac{r}{100}\right)^2 \quad \text{(1)} \] For the second amount: \[ 6655 = P \left(1 + \frac{r}{100}\right)^3 \quad \text{(2)} \] ### Step 2: Form a Ratio Dividing equation (2) by equation (1): \[ \frac{6655}{6050} = \frac{P \left(1 + \frac{r}{100}\right)^3}{P \left(1 + \frac{r}{100}\right)^2} \] This simplifies to: \[ \frac{6655}{6050} = 1 + \frac{r}{100} \] ### Step 3: Calculate the Left Side Calculating the left side: \[ \frac{6655 - 6050}{6050} = \frac{605}{6050} = \frac{1}{10} \] Thus, we have: \[ 1 + \frac{r}{100} = 1.1 \] ### Step 4: Solve for r From the equation: \[ 1 + \frac{r}{100} = 1.1 \] Subtracting 1 from both sides gives: \[ \frac{r}{100} = 0.1 \] Multiplying by 100: \[ r = 10\% \] ### Step 5: Calculate Simple Interest Now, we need to calculate the simple interest on Rs 6,000 at the same rate (10%) for \(5 \frac{3}{4}\) years. Convert \(5 \frac{3}{4}\) years to an improper fraction: \[ 5 \frac{3}{4} = \frac{23}{4} \text{ years} \] ### Step 6: Use the Simple Interest Formula The formula for simple interest (SI) is: \[ SI = \frac{P \times r \times t}{100} \] Where: - \(P = 6000\) - \(r = 10\) - \(t = \frac{23}{4}\) Substituting the values: \[ SI = \frac{6000 \times 10 \times \frac{23}{4}}{100} \] \[ SI = \frac{6000 \times 10 \times 23}{400} \] \[ SI = \frac{1380000}{400} = 3450 \] ### Final Answer The simple interest on a sum of Rs 6,000 at the same rate for \(5 \frac{3}{4}\) years is Rs 3,450. ---
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