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Assertion : In the reaction : MnO(2) ...

Assertion : In the reaction :
`MnO_(2) + 4HCl to MnCl_(2) +2H_(2)O + Cl_(2)`
HCl is getting oxidized while `MnO_(2)` is getting reduced.
Reason : The process in which oxygen is added toa substance is called oxidation whereas the process in which oxygen is removed from a substance is called reduction.

A

Both assertion (A) and reason (R) are true and reason (R) is the correct explanation of assertion (A).

B

Both assertion (A) and reason (R) are true but reason (R) is not the correct explanation of assertion (A).

C

Assertion (A) is true but reason (R) is false.

D

Assertion (A) is false but reason (R) is true.

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Explore conceptually related problems

In the reaction MnO_(2) + 4HCl to MnCl_(2) + 2H_(2)O + Cl_(2) , identify which one is reduced and which one is oxidized ?

Write the following equation in ionic form. MnO_(2)+4HCl to MnCl_(2)+2H_(2)O+Cl_(2)

Knowledge Check

  • In the reaction MnO_(2) + 4HC1 to MnC1_(2) + C1_(2) + 2H_(2)O the substance getting reduced is

    A
    `MnO_(2)`
    B
    HC1
    C
    `MnC1_(2)`
    D
    `C1_(2)`
  • MnO_(2) + 4 HCI rarr MnCI_(2) + 2H_(2)O + CI_(2) . Identify the substance oxidized in the above equation.

    A
    `MnCI_(2)`
    B
    HCI
    C
    `H_(2)O`
    D
    `NbO_(2)`
  • In the reaction 2K MnO_4 + 16 HCl rarr 5Cl_2 + 2MnCl_2 + 2 KCl+ 8H_2O the reduced product is .

    A
    `Cl_2`
    B
    ` KCl`
    C
    ` H_2O`
    D
    `MnCl_2`
  • Similar Questions

    Explore conceptually related problems

    In the reaction : MnO_(2) + 4HCI to MnCl_(2) + 2H_(2)O + Cl_(2) (a) Name the compound (i) oxidised, (ii) reduced. (b) Define oxidation and reduction on its basis .

    Assertion: H_(2)O_(2) reduces Cl_(2) "to" HCl . Reason: H_(2)O_(2) is highly Cl_(2) "to" HCl

    In the following reaction, MnO_(2) + 4HCl rarr MnCl_(2) + 2H_(2)O + Cl_(2) 2 mole MnO_(2) reacts with 4 mol of HCl to form 11.2 L Cl_(2) at STP. Thus, percentage yield of Cl_(2) is:

    In the reaction C_(2) O_(4)^(-2) + MnO_(4)^(-) + H^(+) rarr Mn^(+2) +CO_(2) the reductants is -

    Assertion (A) H_(2)O_(2) reduces Cl_(2) to HCl. Reason (R ) H_(2)O_(2) is called antichlor.