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abs(A)= abs([4,2],[-1,6])...

`abs(A)= abs([4,2],[-1,6])`

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To find the determinant of the matrix \( A = \begin{bmatrix} 4 & 2 \\ -1 & 6 \end{bmatrix} \), we can follow these steps: ### Step 1: Identify the elements of the matrix The matrix \( A \) has the following elements: - \( a_{11} = 4 \) - \( a_{12} = 2 \) - \( a_{21} = -1 \) - \( a_{22} = 6 \) ...
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Knowledge Check

  • The eigenvalues of the matrix is abs([4,-2],[-2,1])

    A
    1,4
    B
    (-1,2)
    C
    0,5
    D
    can not be determined

  • The eigenvectors of the matrix abs([1,2],[0,2]) are written in the form abs([1],[a]) and abs([1],[b]) what is a+b?

    A
    0
    B
    (1/2)
    C
    1
    D
    2

  • If abs(a)=1, abs(b)=2" and "abs(a-2b)=4" then "abs(a+3b) is equal to

    A
    8
    B
    `sqrt(51/2)`
    C
    `sqrt(19/2)`
    D
    `sqrt(77/2)`

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    Solve for x. {:((i)(abs(x)-1)(abs(x)-2) le 0,(ii)(abs(x)-1)/(abs(x)-2) ge 0),((iii)abs(x-3)+abs(4-x)=1,(iv)abs(x)+abs(x+4)=4):}

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