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Find dy/dx if x=acos^3theta, y=bsin^3the...

Find dy/dx if
`x=acos^3theta, y=bsin^3theta`

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Given, `x=acos^3theta, y=bsin^3theta`
`thereforedx/(d theta)=3a cos^2theta.d/(d theta) (costheta)=-3asin thetacos^2theta`
`thereforedy/(d theta)=3bsin^2thetad/(d theta)(sintheta)=3bsin^2thetacostheta`
`thereforedy/dx=dy/((d theta)/(dx/(d theta)))=(3bsin^2thetacostheta)/(-3asinthetacos^2theta)=-b/atantheta`
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MAHAVEER PUBLICATION-DIFFERENTIATION OR DERIVATIVE OF A FUNCTION-QUESTION BANK
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