A particle is moving in a straight line according to the law `S=t^3+2t^2+3t-4`, where S is displacement and t is time. Find the velocity and acceleration when t=2.

Explanation

Given, `S=t^3+2t^2+3t-4`
`therefore` velocity,`v=(dS)/dt=3t^2+4t+3`
and acceleration, `a=(dv)/(dt)=6t+4`
When t=2, velocity, `v=(3.2)^2+4.2+3=23` units.
When t=2, acceleration, a=6.2+4=16 units.