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Find the slope of the tangent to the cur...

Find the slope of the tangent to the curve
`y=x^4-4x^2+8` at (1,5)

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Given curve is `y=x^4-4x^2+8`
`therefore dy/dx=4x^3-8x`
`therefore`Required slope of the tangent to the given curve at (1,5) is
`[dy/dx]_((1,5))=4.1^3-8.1=-4`
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