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Find the equation of the tangents to the curve y=(x-1)(x-2) at the points where the curve cuts the x-axis.

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Find the equation of the tangent to the curve y=(x^3-1)(x-2) at the points where the curve cuts the x-axis.

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Knowledge Check

  • Equation of the tangent to the curve y=2-3x-x^(2) at the point where the curve meets the Y -axes is

    A
    `x+3y=2`
    B
    `3x-y=2`
    C
    `x-3y=2`
    D
    `3x+y=2`
  • The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

    A
    `x+y=e`
    B
    `e(x+y)=1`
    C
    `y+ex=1`
    D
    none of these
  • Equations of tangents to the curve y=x-(1)/(x) at the points where the curve meets the X- axes are

    A
    `y= pm x`
    B
    `y=x pm 1`
    C
    `y=2x pm2`
    D
    `y=3x pm 3`
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    Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point, where it cuts the X-axis.

    Find the equation of the tangent to the curve y=(x-7)/((x-2(x-3)) at the point where it cuts the x-axis.

    Equation of the tangent to the curve y=1-e^((x)/(2)) at the point where the curve cuts y -axis is

    Find the equation of the tangent to the curve y=sec x at the point (0,1)

    Equation of the tangent to the curve y= e^(-abs(x)) at the point where it cuts the line x=1-