Find the slope of the tangent to the curve
`y(x^2+1)=x` at the point (1, 1/2)

Explanation

To find the slope of the tangent to the curve defined by the equation \( y(x^2 + 1) = x \) at the point \( (1, \frac{1}{2}) \), we will follow these steps:

### Step 1: Differentiate the equation implicitly.
We start with the equation:
\[ y(x^2 + 1) = x \]
To find the derivative \( \frac{dy}{dx} \), we will differentiate both sides with respect to \( x \).
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