If `xsqrt(1-y^2)+ysqrt(1-x^2)=0`, find the value of `(d^2y)/dx^2` when y=1

Explanation

To find the value of \(\frac{d^2y}{dx^2}\) when \(y = 1\) for the equation \(x\sqrt{1 - y^2} + y\sqrt{1 - x^2} = 0\), we will follow these steps:

### Step 1: Substitute \(y = 1\) into the equation
Substituting \(y = 1\) into the equation gives:
\[ x\sqrt{1 - 1^2} + 1\sqrt{1 - x^2} = 0 \]
This simplifies to:
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