Find the maximum and minimum values of the function `y=4x^3-3x^2-6x+1`

Explanation

To find the maximum and minimum values of the function \( y = 4x^3 - 3x^2 - 6x + 1 \), we will follow these steps:

### Step 1: Find the first derivative
We start by differentiating the function with respect to \( x \).

\[ y' = \frac{dy}{dx} = \frac{d}{dx}(4x^3 - 3x^2 - 6x + 1) \]
...