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int(0)^(pi)(x tanx)/(secx+cosx)dx is...

`int_(0)^(pi)(x tanx)/(secx+cosx)dx` is

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Evaluate the following : int_(0)^(pi)(x tan x)/(secx+cos x)dx

Evaluate the following : int_(0)^(pi)(x tanx)/(secx "cosec x")dx

int_(0)^(pi)(x tanx)/((secx+cosx))dx=(pi^(2))/(4)

int_(0)^(pi)(x tanx)/((secxcosecx))dx=(pi^(2))/(4)

int_(0)^(pi//2)(x)/(sinx+cosx)dx .

Prove that int_(0)^(pi)(xtanx)/((secx+tanx))dx=pi((pi)/(2)-1) .

int_(0)^(pi/3)(x)/(1+secx)dx

If A=int_(0)^(pi)(sinx)/(sinx+cosx)dx and B=int_(0)^(pi)(sinx)/(sinx-cosx)dx , then

If A=int_(0)^(pi)(sinx)/(sinx+cosx)dx, B=int_(0)^(pi)(sinx)/(sinx-cosx)dx , then

int_0^pi (xtanx)/(secx+tanx)dx

MAHAVEER PUBLICATION-DEFINITE INTEGRAL-QUESTION BANK
  1. Using the properties of definite integral,show that int0^(pi/2) log ta...

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  2. Evaluate: int0^pi(xsinx)/(1+cos^2x)dx

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  3. int(0)^(pi)(x tanx)/(secx+cosx)dx is

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  4. The value of int(0)^( pi/2)(sqrt(cos x))/(sqrt(sin x)+sqrt(cos x))dx

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  5. int(pi/3)^(pi/6)(dx)/(1+sqrttanx)

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  6. Evaluate int0^(pi/2) sinx/(sinx + cosx) dx

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  7. Evaluate: int0^pi x/(a^2cos^2x+b^2sin^2x)dx

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  8. Evaluate lim(nrarroo) [1/(n+1) + 1/(n+2) + 1/(n+3) +…+ 1/(2n)]

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  9. lim(n->oo)1/n[tan (pi/(4n))+tan((2 pi)/(4n))+...tan((npi)/(4n))]

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  10. Evaluate lim(nrarroo) [1/(n+k) + 1/(n+2k) + 1/(n+3k) +…+ 1/(n+nk)]

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  11. Evaluate lim(nrarroo) n [1/(n^2+1^2) + 1/(n^2+2^2) + 1/(n^2+3^2) +…+ 1...

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  12. lim(n to oo)[(sqrt(n+1)+sqrt(n+2)+....+sqrt(2n))/(n sqrt((n)))]

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  13. Evaluate lim(nrarroo) [1/(n+1) + 1/(n+2) + 1/(n+3) +…+ 1/(2n)]

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  14. Evaluate lim(nrarroo) [(1^6 + 2^6 + 3^6…..+n^6)/n^7]

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  15. Choose the correct Answer of the Following Questions : int(pi/4)^(pi/2...

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  16. Choose the correct Answer of the Following Questions : int0^1 1/(2x-3)...

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  17. Choose the correct Answer of the Following Questions : int1^4 x^(-1/2)...

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  18. Choose the correct Answer of the Following Questions : int0^pi (1/(1+s...

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  19. Choose the correct Answer of the Following Questions : int0^(2pi) sqrt...

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  20. Choose the correct Answer of the Following Questions : int0^(pi/2) sqr...

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