Using the properties of definite integral Evaluate : `int_0^(pi) x /(1 + sinx) dx `

Explanation

To evaluate the integral \( I = \int_0^{\pi} \frac{x}{1 + \sin x} \, dx \), we can use the property of definite integrals which states that:

\[ \int_0^a f(x) \, dx = \int_0^a f(a - x) \, dx \]

In this case, we have \( a = \pi \). Therefore, we can rewrite the integral as:

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