A stone is thrown vertically upwards and after ascending a height 'h' it comes back to the hands of the thrower. What is the (i) total distance covered and the (ii) net displacement of the stone?

Explanation

To solve the problem, we need to analyze the motion of the stone when it is thrown vertically upwards and then comes back to the thrower's hands.

### Step-by-Step Solution:

1. **Understanding the Motion**:
- When the stone is thrown upwards, it travels a distance 'h' to reach its maximum height.
- After reaching the maximum height, it falls back down the same distance 'h' to return to the thrower's hands.

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