The line 3x - 5y = -10 cuts y-axis at

Options

A. `(0.2)`
B. `(0.1)`
C. `(0.3)`
D. `(0.4)`

Answer

To find where the line \(3x - 5y = -10\) cuts the y-axis, we need to determine the y-coordinate when \(x = 0\).

### Step-by-step Solution:

1. **Start with the given equation**:
\[ 3x - 5y = -10 \]

2. **Substitute \(x = 0\)** into the equation to find the y-coordinate:
\[ 3(0) - 5y = -10 \]
This simplifies to:
\[ -5y = -10 \]

3. **Solve for \(y\)**:
Divide both sides by -5:
\[ y = \frac{-10}{-5} = 2 \]

4. **Write the coordinates of the point where the line cuts the y-axis**:
Since \(x = 0\) and \(y = 2\), the coordinates are:
\[ (0, 2) \]

5. **Conclusion**:
The line \(3x - 5y = -10\) cuts the y-axis at the point \((0, 2)\).