Home
Class 10
MATHS
The perimeters of two similar triangles ...

The perimeters of two similar triangles are 25 cm and 15 cm respectively. If one side of the first triangle is 9 cm, then the corresponding side of second triangle is .........

Text Solution

AI Generated Solution

The correct Answer is:
To find the corresponding side of the second triangle, we can use the property of similar triangles, which states that the ratio of the perimeters of two similar triangles is equal to the ratio of their corresponding sides. ### Step-by-Step Solution: 1. **Identify the given values:** - Perimeter of the first triangle (P1) = 25 cm - Perimeter of the second triangle (P2) = 15 cm - One side of the first triangle (S1) = 9 cm - Let the corresponding side of the second triangle be S2. 2. **Set up the ratio of the perimeters:** \[ \frac{P1}{P2} = \frac{S1}{S2} \] Substituting the known values: \[ \frac{25}{15} = \frac{9}{S2} \] 3. **Cross-multiply to solve for S2:** \[ 25 \cdot S2 = 15 \cdot 9 \] 4. **Calculate the right side:** \[ 15 \cdot 9 = 135 \] So we have: \[ 25 \cdot S2 = 135 \] 5. **Divide both sides by 25 to isolate S2:** \[ S2 = \frac{135}{25} \] 6. **Simplify the fraction:** \[ S2 = 5.4 \text{ cm} \] ### Final Answer: The corresponding side of the second triangle is **5.4 cm**.
Promotional Banner

Topper's Solved these Questions

  • C.B.S.E 2020 CLASS -X (DELHI)

    OSWAL PUBLICATION|Exercise DELHI SET -I ( SECTION-B )|8 Videos
  • C.B.S.E 2020 CLASS -X (DELHI)

    OSWAL PUBLICATION|Exercise DELHI SET -I ( SECTION-C )|20 Videos
  • ARITHMETIC PROGRESSIONS

    OSWAL PUBLICATION|Exercise CASE - BASED MCQs |15 Videos
  • C.B.S.E 2020 CLASS -X (OUTSIDE DELHI)

    OSWAL PUBLICATION|Exercise OUTSIDE DELHI SET -III ( SECTION- D ) |2 Videos

Similar Questions

Explore conceptually related problems

The perimeter of two similar triangles are 24cm and 16cm, respectively. If one side of the first triangle is 10cm, then the corresponding side of the second triangle is

The perimeters of two similar triangles are 25cm and 15cm respectively.If one side of first triangle is 9cm, what is the corresponding side of the other triangle?

The perimeters of two similar triangles are 30cm and 20cm respectively.If one side of the first triangle is 12cm, determine the corresponding side of the second triangle.

The perimeters of two similar triangles are 25cm and 15cm respectively. If one side of the first triangle is 9cm, find the length of the corresponding side of the second triangle. OR In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC. Prove that 9 AD^(2)=7AB^(2)

the perimeters of two similar triangles are 40 cm and 30 cm respectively. If one side of the first traingle is 21 cm. Determine the corresponding side of the second triangle.

The perimeters of two similar triangles are 30 and 20 cm respectively side of first triangle is 9 cm. Determine the corresponding side of the second triangle.

The perimeters of two similar triangles are 30 cm and 20 cm respectively. If one side of the first triangle is 9 cm long, find the length of the corresponding side of the second triangle.

The areas of two similar triangles are 25 cm^(2) and 36 cm^(2) respectively. If the altitude of the first triangle is 3.5 cm then the corresponding altitude of the other triangle is

Areas of two similar triangles are 225 sq cm and 81 sq cm. If a side of the smaller triangle is 12 cm, then find the corresponding side of the bigger triangle.