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x-axis divides the line segment joining ...

x-axis divides the line segment joining A(2, -3) and B(5,6) in the ratio :

A

`2:3`

B

`3:5 `

C

`1:2`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio in which the x-axis divides the line segment joining the points A(2, -3) and B(5, 6), we can follow these steps: ### Step 1: Identify the coordinates of points A and B. - A(2, -3) - B(5, 6) ### Step 2: Understand that the x-axis has a y-coordinate of 0. - The point where the x-axis intersects the line segment will have coordinates (x, 0). ### Step 3: Use the section formula. The section formula states that if a point P divides the line segment joining points A(x1, y1) and B(x2, y2) in the ratio m1:m2, then the coordinates of point P are given by: \[ P\left(\frac{m1 \cdot x2 + m2 \cdot x1}{m1 + m2}, \frac{m1 \cdot y2 + m2 \cdot y1}{m1 + m2}\right) \] ### Step 4: Set the y-coordinate of the dividing point to 0. Since we want the y-coordinate to be 0 (because it lies on the x-axis), we set up the equation: \[ \frac{m1 \cdot 6 + m2 \cdot (-3)}{m1 + m2} = 0 \] ### Step 5: Solve the equation for the ratio. Multiplying both sides by (m1 + m2) gives: \[ m1 \cdot 6 + m2 \cdot (-3) = 0 \] This simplifies to: \[ 6m1 = 3m2 \] Dividing both sides by 3 gives: \[ 2m1 = m2 \] Thus, we can express the ratio: \[ \frac{m1}{m2} = \frac{1}{2} \] ### Step 6: Write the final answer. The x-axis divides the line segment joining A(2, -3) and B(5, 6) in the ratio **1:2**. ---
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Knowledge Check

  • Find the coordinate of the point which divides the line segment joining A(1,-2,3) and B(3,4,-5) in the ratio 2:3 externally.

    A
    `(3,14,19)`
    B
    `(-3,-14,19)`
    C
    `(-3,14,19)`
    D
    None of these
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