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Find c if the system of equations cx + 3...

Find c if the system of equations cx + 3y + (3 - c) = 0 , 12 x + cy - c = 0 has infinitely many solutions ?

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To find the value of \( c \) such that the system of equations 1. \( cx + 3y + (3 - c) = 0 \) 2. \( 12x + cy - c = 0 \) has infinitely many solutions, we need to ensure that the coefficients of the equations are proportional. ### Step-by-step Solution: **Step 1: Write the equations in standard form.** The equations can be rewritten as: 1. \( cx + 3y = c - 3 \) 2. \( 12x + cy = c \) **Hint:** Rearranging the equations helps in identifying the coefficients clearly. --- **Step 2: Identify the coefficients.** From the first equation \( cx + 3y = c - 3 \), the coefficients are: - Coefficient of \( x \): \( c \) - Coefficient of \( y \): \( 3 \) - Constant term: \( c - 3 \) From the second equation \( 12x + cy = c \), the coefficients are: - Coefficient of \( x \): \( 12 \) - Coefficient of \( y \): \( c \) - Constant term: \( c \) **Hint:** Coefficients are essential for establishing the proportionality condition. --- **Step 3: Set up the proportionality condition.** For the equations to have infinitely many solutions, the ratios of the coefficients must be equal: \[ \frac{c}{12} = \frac{3}{c} = \frac{c - 3}{-c} \] **Hint:** Remember that for two lines to coincide, the ratios of their coefficients must be equal. --- **Step 4: Solve the first ratio \( \frac{c}{12} = \frac{3}{c} \).** Cross-multiplying gives: \[ c^2 = 36 \] Thus, \[ c = 6 \quad \text{or} \quad c = -6 \] **Hint:** When cross-multiplying, ensure to check both positive and negative roots. --- **Step 5: Solve the second ratio \( \frac{3}{c} = \frac{c - 3}{-c} \).** Cross-multiplying gives: \[ 3(-c) = c(c - 3) \] This simplifies to: \[ -3c = c^2 - 3c \] Rearranging leads to: \[ 0 = c^2 \] Thus, \[ c = 0 \] **Hint:** Always simplify equations carefully to avoid losing solutions. --- **Step 6: Analyze the results.** From the first ratio, we found \( c = 6 \) or \( c = -6 \). From the second ratio, we found \( c = 0 \). To have infinitely many solutions, we need to check which of these values satisfy both conditions. **Final Decision:** The only consistent value that satisfies the proportionality condition for both equations is \( c = 6 \). ### Final Answer: Thus, the value of \( c \) for which the system of equations has infinitely many solutions is \( c = 6 \). ---
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