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At temperature of 298 K , the emf of the...

At temperature of 298 K , the emf of the following electrochemical cell
`Zn_((s))` will
`|Zn^(2+)(10^(-4)M)||Cu^(2+)(10^(-4)M)|Cu_((s))`
be --- V.
(Given `E_("cell")^(@)=1.10V` )

Text Solution

Verified by Experts

The correct Answer is:
`1.10`
For the given electrochemical cell, the cell reaction will be as follows:
`underset((" Oxiddation at anode"))(ZntoZn^(2+)+2e^(-))`
`(Cu^(2+)+2e^(-)toCu"(Reduction at cathode)")/(Cu^(2+)+ZntoCu+Zn^(2)"(Ovemll cell reaction)")`
`:.` The e.m.f. of the cell is given by
`E_("cell")=E_("cell")^(**)-(0.0591)/(n)log_(10)""([Zn^(2+)])/([Cu^(2+)])`
Substituting the values in above equation,
`E_("cell")=1.10-(0.0591)/(2)log_(10)""(10^(-4))/(10^(-4))`
`=1.10-(0.0591)/(2)xx0`
`=1.10V`
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