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The vapour pressure of pure benzene at a...

The vapour pressure of pure benzene at a certain temperature is 650 mm Hg. A non-volatile and non-electrolyte solid weighing 1.54g is added to 26.00 g of benzene. The vapour pressure of the solution is 600 mm Hg. The molecular weight of solid substance is ____g `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
60.06
`(p_(A)^(@)-p_(T))/(p_(A)^(@))=(650-600)/(650)=(1)/(13)`
`:.(p_(A)^(@)-p_(T))/(p_(A)^(@))=(W_(B))/(M_(B))xx(M_A)/(W_(A)),(1)/(13)=(1.54xx78)/(M_(B)xx26.00)`
`:.M_(B)=(1.54xx78xx13)/(26.00)=60.06gmol^(-1)`
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