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For sodium light, the two yellow lines o...

For sodium light, the two yellow lines occur at `lambda_(1) and lambda_(2)` wavelengths. If the mean of these two is `6000Å` and `|lambda_(2)-lambda_(1)|=6Å`, then the approximate energy difference between the two levels corresponding to `lambda_(1) and lambda_(2)` is

A

`2 xx 10^(-3)eV`

B

`2eV`

C

2000 e V

D

`2 xx 10^(-6)eV`

Text Solution

Verified by Experts

The correct Answer is:
A
`(lambda_(1)+lambda_(2))/(2)=6000 ....`
`Delta E=(12400)/(lambda_(2))-(12400)/(lambda_(1))`
Solving eq. (1) and
`lambda_(2)-lambda_(1)=6` gives
`Delta E=2 xx 10^(-3)eV`
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