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A hole in the horizontal bottom of the c...

A hole in the horizontal bottom of the container is closed by a hemispherical cap of radius R (see figure) The vessel is filled with liquid of density d. Bottom is at a depth of H. Find the force with which the cap presses down on the bottom of the vessel. Neglect atmospheric pressure. If the force is api N, fill 'a' in the OMR sheet (Take `d=10^(3)kg//m^(3), H=1m, R=30cm)`

Text Solution

Verified by Experts

The correct Answer is:
720.00`


`therefore F_(y)=rho gH pi R^(2)-(2)/(3)pi R^(3) rho g`
`= pi(0.3)^(2) xx 1 xx 10^(3) xx 10`
`-(0.3)^(3)xx 10^(3) xx 10`
= 720 `pi`
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