Home
Class 12
PHYSICS
An open pipe 40 cm long and a closed pip...

An open pipe 40 cm long and a closed pipe 31 cm long, both having same dimeter, are producing their first overtone, and these are in unison. The end correction of these pipes is :

Text Solution

Verified by Experts

The correct Answer is:
2

`lambda=(upsilon)/(f)`
For open pipe :
`lambda_(1)=l+2e=40+2e`
`implies(upsilon)/(f)=40+2e`
For closed pipe : `lambda_(2)=l+e`
`implies (3)/(4) lambda_(1)=31+e[ because lambda_(c)=(3)/(4)lambda_(0)]`
`implies (3)/(4)((upsilon)/(f))=31+e..........(ii)`
From (i) and (ii)
`(3)/(4)(40+2e)=31+e`
`implies e=2 cm`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 30

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos
  • NTA TPC JEE MAIN TEST 124

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos
  • NTA TPC JEE MAIN TEST 36

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

An open pipe 30 cm long and a closed pipe 23 cm long both of the same diameter, are each sounding their first overtone, and these are in unison. What is the end correction of these pipes?

The first overtone of a closed pipe is given by –

An open pipe and a closed pipe are in resonance with each other with their first overtones. The ratio of their lengths are

The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe 2 m long. The length of the open pipe is

Compare the length of a closed organ pipe and an open organ pipe, if the second overtone of the open pipe is unison with the second overtone of the closed organ pipe.

if the first overtone of a closed pipe of length 50 cm has the same frequency as the first overtone of an open pipe, then the length of the open pipe is

An open organ pipe is closed suddenly with the result that the second overtone of the closed pipe is found to be higher in frequency by 100 than the first overtone of the original pipe. Then, the fundamental frequency of the open pipe is