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A radioactive nucleus is being produced ...

A radioactive nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lamda`. If `N_0` are the number of nuclei at time `t = 0`, then maximum number of nuclei possible are.

Text Solution

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The correct Answer is:
1
`underset(a)rarr X^(**)underset(b)rarrY`
Let the initial number of the
particles of X at t=0 be `N_(0)` . Its
number at t = t be N.
Then, `(dN)/(dt)=+a-bN`
For
`N_(max)(dN)/(dt)=0 implies a-bN=0`
` implies N_(max)=(a)/(b)`
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