Home
Class 12
PHYSICS
Two identical triangular sets are used ...

Two identical triangular sets
are used to measure the length
of a rod. The division on the
triangles are equally spaced. If
the length of the rod is found to
be 6.5 mm then calculate the
division length (in mm).

Text Solution

Verified by Experts

The correct Answer is:
2

Suppose one division length is l.
Then, size of main scale division ,
`AB=(l)/(ocs(37^(@)))=(5l)/(4)`
Least count of the calliper wil be ,
LC=1MSD-1VSD
`implies LC=(5l)/(4)-l=(l)/(4)`
The main scale reading is two and
the third vernier scale is coinciding
with the main scale.
So. length of the rod.
6.5 mm= 2MSD + 3LC
`implies 6.5 mm=2(5l)/(4)+3(1)/(4)`
`implies 1=2 mm`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 30

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos

  • NTA TPC JEE MAIN TEST 124

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

  • NTA TPC JEE MAIN TEST 36

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

The length of a rod is 5 xx 10^(2) m , the order of magnitude of the length of the rod is

The length of a rod is measured as 31.52 cm . Graduations on the scale are up to

To determine the diameter of a rod a student wound a thread 5 times round the rod and measured the length of thread as 156 mm on a metre scale. Using this value he calculated the diameter of the rod. If the actual diameter of the rod is 9.94 mm, what is the error that could result in the method followed by the student? Take (pr+q)/(2)

A student measured the length of a rod and wrote it as 3.50cm . Which insturment did he use to measure it?

Two wires A and B of same material and of equal length with the radii in the ratio 1 : 2 are subjected to identical loads. If the length of A increases by 8 mm, then the increase in length of B is

A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it ?