A rod of mass M and length l is suspende...

A rod of mass M and length l is suspended by two wires P and Q. A uniform magnetic field 'B' is directed into the page. When current through the rod is l. Then the tension in each supporting wire is-

`(mg)/2`

2BIl

`Mg - Bil`

`(Mg - Bil)/2`

Text Solution

Verified by Experts

The correct Answer is:

`mg - Bil = 2T`

`T = (mg - BIC)/2`

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