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Let force F, length L and time T be take...

Let force F, length L and time T be taken as fundamental units, then what will be the dimensional formula for mass?

A

`[FL^(-1)T^2]`

B

`[FLT^(-2)]`

C

`[FL^(-1)T^(-1)]`

D

`[FL^5T^2]`

Text Solution

Verified by Experts

The correct Answer is:
A
By second law of motion `F = ma " So, " m= F/a`
By principle of homogeneity `[m] = [F/a] =F^1/(L^1T^(-2)) =F^1L^(-1)T^2`
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Knowledge Check

  • Treating force F, length L and time T as fundamental units, what is the dimensional formula of mass?

    A
    `F^(+1)L^(+2)T^(+1)`
    B
    `F^(+2)L^(+1)T^(-1)`
    C
    `F^(+1)L^(-1)T^(+2)`
    D
    `F^(+1)L^(+1)T^(+2)`

  • If force F , Length L and time T are chosen as fundamental quantites, the dimensional formula for Mass is

    A
    `[FLT]`
    B
    `[F^(-1) L^(-1) T^(-2)]`
    C
    `[F^(-2) L^(-2) T^(-2)]`
    D
    `[F^(1) L^(-1) T^(2)]`

  • If the energy (E), velocity (v) and force (F) are taken as fundamental quantities, then what is the dimensional formula for mass?

    A
    `E^(1)v^(2)F^(1)`
    B
    `F^(1)v^(-1)E^(1)`
    C
    `E^(1)v^(-2)F^(0)`
    D
    `F^(1)v^(-2)E^(0)`

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