Home
Class 12
PHYSICS
An infinite ladder network is constructe...

An infinite ladder network is constructed with `1Omega `and `2Omega` resistors as shown. Find the equivalent resistance points `A` and `B`.

A

`1Omega`

B

`2Omega`

C

`3Omega`

D

`5//8Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=(2x)/(x+2) +1`

`x^(2) +2x =2x+x+2`
`x^(2) -x -2 =0`
`(x-2) (x+1)=0`
`x=2Omega`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 47

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos

  • NTA TPC JEE MAIN TEST 46

    NTA MOCK TESTS|Exercise PHYSICS|30 Videos

  • NTA TPC JEE MAIN TEST 48

    NTA MOCK TESTS|Exercise PHYSICS |29 Videos

Similar Questions

Explore conceptually related problems

An infinite ladder is constructed with 1 Omega and 2 Omega resistors as shown in Fig 27-49. Find the effective resistance between the points A and B.

An infinite ladder is constructed with 1(Omega) and 2(Omega) resistor as shown in figure.(a)Find the effective resistance between the point A and B. (b) Find the current that passes through the (2 Omega) resistor nearest to the battery.

The network of resistors. Find the equivalent resistance between points A and D.

An infinite ladder network is arranged with resistances R and 2 R as shown. The effective resistance between terminals A and B is

Thre figure shows a network of resistor each heaving value 12 Omega . Find the eqivanlent resistance between points A and B .

An infinite network of resistances has been made as shown in the figure. Each resistance is R. find the equivalent resistance between A and B.

In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is

Each resistance is of 1Omega in the circuit diagram shown in figure. Find out equivalent resistance between A and B.

For infinite ladder network containing identical resistance of R Omega each, are combined as shown in figure. The equivalent resistance between A and B is R_(AB) and between A and C is R_(AC) . Then the value (R_(AB))/(R_(AC)) is :