Home
Class 12
PHYSICS
The specific resistance of a wire is rho...

The specific resistance of a wire is `rho`, its volume is `3 m^(3)` and its resistance is `3 ohms`, then its length will be

A

`sqrt(1//rho)`

B

`3//sqrt(rho)`

C

`sqrt(3)//rho`

D

`rho//sqrt(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

`R=(rho l)/(A) =(rho l)/(V//l) =(rho l^(2))/(V)`
or `l=((RV)/(rho))^(1//2) =((3xx3)/(rho))^(1//2) = (3)/(sqrt(rho))`
Promotional Banner

Topper's Solved these Questions

  • NTA TPC JEE MAIN TEST 55

    NTA MOCK TESTS|Exercise PHYSICS (SUBJECTIVE NUMERICAL)|10 Videos
  • NTA TPC JEE MAIN TEST 54

    NTA MOCK TESTS|Exercise PHYSICS|30 Videos
  • NTA TPC JEE MAIN TEST 56

    NTA MOCK TESTS|Exercise PHYSICS |30 Videos

Similar Questions

Explore conceptually related problems

The resistivity of a wire is rho, its volume is 3m ^(3) and resistance is 3 Omega, then its length will be

Specific resistance of a wire depends on its

How does the resistance of a wire depend on its length ?

The resistance of a wire is R ohm. What will be its new resistance if it is stretched to n times its original length ?

The resistance of a wire is r ohm. If it is melted and stretched to n times its original length , its new resistance will be

The temperature coefficient of resistance of a wire is 0.00125 per ^@C . At 300K, its resistance is 1 ohm. This resistance of the wire will be 2 ohm at.

The resistance of a wire is 'R' ohm. If it is melted and stretched to n times its origianl length, its new resistance will be

A wire of resistance 1 Omega is stretched to double its length. Then its resistance becomes

If a resistive wire is elongated, its resistance?