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When a particle accelerated with 200 V p...

When a particle accelerated with 200 V potential its de Broglie wavelength is `10^(-10)`m. Find the wavelength (in Å) of the same particle if it is accelerated by 800 V.

Text Solution

Verified by Experts

The correct Answer is:
`00.50`
By using `lambda.sigma(1)/(sqrt(V))`
`(lambda_(1))/(lambda_(2))= sqrt((v_(2))/(V_(1)))`
`:. (10^(-10))/(lambda_(2))=sqrt((800)/(200))=2`
`:.lambda_(2)=0.5A`
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