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Assume that a drop of liquid evaporates ...

Assume that a drop of liquid evaporates by decreases in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is `rho` and L is its latent heat of vaporization.

A

`T//rho L `

B

`2T //rho L `

C

`rho L //T`

D

`sqrt(T//rhoL)`

Text Solution

Verified by Experts

The correct Answer is:
B
When radius is decreased by dr
Decrease in surface energy = Heat required for vaporisation
`(8pi r dr) xx T = 4pi r^(2) dr rho L rArr r=(2T)/(rho L)`
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