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The rate of attenuation of a 10 Km long ...

The rate of attenuation of a 10 Km long channel is -2 dB / Km. If a 1 KW signal is transmitted in this channel so what will the power of the signal (in W) received ?

Text Solution

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The correct Answer is:
`10.00`
Loss suffered in the communication channel
`= (-2)10 = –20` dB
`:.10 log((p_(s))/(p)) = -20 rArr log((p_(p))/(p_(i)))= -2`
`:. ((P_(t))/(P_(t)))=10^(-2) =(1)/(100)`
`:.P_(0)=(P_(i))/(100)=(1000)/(100)=10W`
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