A circular ring of weight 4kg and radius 60 cm is suspended on a horizontal nail at its circumference. The frequency of oscillation for small oscillations was found to be____Hz. (Take `sqrt(8.17)=2.85`)

Answer

`0.45`

Explanation

For a hoop, `I_(0)= mr^(2) = mk^(2)`
`:.k^(2) =r^(2) rArr l= r` (given)
`:.T=2pi sqrt((k^(2)+t^(2))/(l g)) =2pi sqrt((r^(2) +r^(2))/(r g))=2pi sqrt((2r)/(g))`
`=2pi sqrt((1.2)/(9.8))`
Frequency `(v)=(1)/(T) =(1)/(2pi) sqrt((9.8)/(1.2))`
`:.v=0.45s^(-1)`