A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

Options

A. `h/9` metre from the ground
B. `(7h)/9` metre from the ground
C. `(8h)/9` metre from the ground
D. `(17h)/18` metre from the ground

Answer

C

Explanation

Displacement of particle in T second if particle is dropped
`h= 1/(2)gT^2`
At `T/3` second, distance fallen
`d=1/2g(T/3) =h/9`
Height from ground =
`=h- d = (8h)/9`