If light travels a distance `x` in `t_(1)` sec in air and `10x` distance in `t_(2)` sec in a medium, the critical angle of the medium will be

Options

A. `sin^(-1)((20t_1)/(t_2))`
B. `sin^(-1)((10t_1)/(t_2))`
C. `sin^(-1)((t_1)/(t_2))`
D. `sin^(-1)((t_2)/(10t_1))`

Answer

B

Explanation

`mu=(x/t_1)/((10x)/2)=t_2/(10t_1)`
`sintheta_C=1/(t_2//10t_1)=(10t_1)/t_2implies theta_C`
`=sin^(-1)((10t_1)/t_2)`