In a particular photoelectric setup it is observed that the maximum velocity of emitted photoelectrons is `4.4 ms^(-1)`. If it is known that `e//m` ratio for electrons is `1.76 xx 10^11 C kg^(-1)`, then the stopping potential for this setup will be given by `........ xx 10^11 JC^(-1)`

Explanation

To find the stopping potential in the given photoelectric setup, we can use the relationship between the kinetic energy of the emitted photoelectrons and the stopping potential.

### Step-by-Step Solution:

1. **Calculate the Kinetic Energy (KE) of the emitted photoelectrons:**
The kinetic energy of an electron can be calculated using the formula:
\[
KE = \frac{1}{2} mv^2
...