A flux of 1m Wb passes through a strip having an area `A=0.02 m^(2)`. The plane of the strip is at an angle of `60^(@)` to the direction of a uniform field B. The value of B is-

Options

A. 0.1 T
B. 0.058 T
C. 4.0 mT
D. None of the above

Answer

B

Explanation

We know that, `phi = BA cos theta`
Angle between `vecA` and `vecB` is `30^(@)`
`phi = 1 xx 10^(-3) Wb`
`A = 0.02 m^(2)`
`rArr 10^(-3) = B xx 2 xx 10^(-2) xx cos 60^(@)`
`rArr B = 0.058 T`