If only one hundredth part of total current flowing in the circuit is to be passed through a galvanometer of resistance `G Omega`, Then the value of shunt resistance required will be-

Options

A. `G/10`
B. `G/100`
C. `G/99`
D. `G/999`

Answer

C

Explanation

Using Kirchoff.s Loop law:
`i_(g)G =(i-i_(g))S`
`i/100 G =(i-i/100)S` `G/100 = (99 S)/100`
`S = G/ 90`