A mass (M) attached to a spring, oscillates with a period of (2 sec). If the mass in increased by (2 kg) the period increases by one sec. Find the initial mass (M) assuming that Hook's Law is obeyed.

Answer

`1.6`

Explanation

`T = 2pisqrt(M/K)` or `T prop sqrt(M), T_(2)/T_(1) = sqrt(M_(2)/M_(1))`
`therefore 3/2 = sqrt((M+2)/M)`
Solving this equation we get, M = 1 .6 kg.