Coefficient of thermal conductivity is the product of heat, distance and reciprocal of (area x difference in temperature x time). The new value of a unit of coefficient of thermal conductivity, if fundamental units are 21.6 kg, 1 decimetre, 4 K and 1 minute will be ______ `xx 10^(-6)` new units.

Answer

`02.50`

Explanation

Coefficient of thermal conductivity, k = `(Q xx l)/(A xx Deltatheta xx t)`
`rArr K = ((ml^(2))/t^(2) xx 1)/(1^(2) xx Deltatheta xx t)`
`rArr K = (m xx l)/(Deltatheta xx t^(3)) = (21.6 xx 0.1)/(4 xx (60)^(2))`
`= 2.5 xx 10^(-6)` new units.